Therefore:A. (2,400π - 3,600√3) cm²
Area of segment (the shaded region) = Area of sector - area of triangle
Area of sector = (θπ/360)r²
Area of segment = (sinθ/2)r²
Derive the equation:
Area of segment = (θπ/360)r² - (sinθ/2)r²Area of segment = r²(θπ/360 - sinθ/2)
Central angle, θ = 60°
Radius, r = 120 cm
pi, π ≈ 3.14
Solve for the area of segment or shaded region:
Area of segment = r²(θπ/360 - sinθ/2)
Area = (120 cm)² [60×3.14/360 - sin60/2]
Area = 14,400 cm² [0.523 - 0.866/2]
Area = 14,400 cm² [0.523 - 0.433]
Area = 14,400 cm² (0.09)Area of segment or shaded region = 1,296 cm² or 1,300 cm²
A. (2,400π - 3,600√3) cm² = 1,300 cm²
B. 3,600√3 = 6,235 cm²
C. 2,400π = 7,536 cm²
D. (14,400π - 3,600√3) = 38,980 cm²
15 minutes per second
Since s=d/t, we divide 120 m by 8 sec, making the answer 15 m/s
I think my mind just said it's B
The area is approximately 1300.8 cm² or
Consider the provided information.
We need to find the area of the shaded region.
The area of the segment is given as:
It is given that θ = 60°, r = 120 cm
Substitute the respective values in the above formula.
Now substitute π = 3.14
Hence, the area is approximately 1300.8 cm² or
right has a radius of 120 cm. find the area o...