Hannah has p275 consisting of 10-peso coins and 5-peso coins. if she has 10 more than 5-peso than 10-peso coins, how many of each kind does she have?

show the solution pls

25 ₱5 coins

15 ₱10 coins

Step-by-step explanation:

If she has 10 ₱5 coins than ₱10 coins, then

₱5 × 10 = ₱50

₱275 - ₱50 = ₱225

To find the number of coins she have:

10 + 5 = 15

225 ÷ 15 = 15

Since she has 10 more ₱5 coins:

15 + 10 = 25

To check:

₱10 × 15 = ₱150

₱5 × 25 = ₱125

₱150 + ₱125 = ₱275

41, 5 peso coins and 7, 10 peso coins hope it helps

let x = numbers of 10-peso coin

and

x + 10 = numbers of 5-peso coin

thus,

total money = P275

amount with 10 peso coins = x(10 pesos) = 10x

amount consisting 5 peso coins = (x+10)(5peso) = 5x + 50

thus,

          amount with 10 peso coins + amount with 5 peso coins = 275

                                                   10x + 5x + 50 = 275

                                                                    15x = 275 - 50

                                                                    15x = 225

                                                                        x = 15

                                                therefore, there are 15 - ten peso coins

no. of 5-peso coins = x + 10

                                 = 15 + 10 = 25

therefore, thereare 25-  five peso coins

check:

    P10.00 x 15 = 150

    P5.00 x 25 =  125

TOTAL                P275