This expression can be factored with Difference of Two Cubes Formula:
x^3 – y^3 = (x – y)(x^2 + xy + y^2), where x = a^3 and y = 4b^4. You'll get a^3 and 4b^4 by cube rooting each term.
x^3 – y^3 = (x – y)(x^2 + xy + y^2)
a^9 - 64b^12 = (a^3 - 4b^4) [ (a^3)^2 + (a^3 )(4b^4) + (4b^4)^2 ]
= (a^3 - 4b^4)(a^6 + 4a^3 4b^4 + 16b^8)
the answer is false..